\({}^{n}P_r={}^{n}P_s\) और \(r\neq s\) generally क्यों संभव नहीं होता?
Why is \({}^{n}P_r={}^{n}P_s\) with \(r\neq s\) generally not possible?
Explanation opens after your attempt
A. क्योंकि \(^{n}P_r\) usually (r) बढ़ने पर extra positive factors से बदलता हैBecause \(^{n}P_r\) usually changes by extra positive factors as (r) increases
Concept
Permutations do not have complement symmetry, and changing length changes the count. In exams do not apply combination symmetry to permutations.
Why this answer is correct
The correct answer is A. क्योंकि \(^{n}P_r\) usually (r) बढ़ने पर extra positive factors से बदलता है / Because \(^{n}P_r\) usually changes by extra positive factors as (r) increases. Permutations do not have complement symmetry, and changing length changes the count. In exams do not apply combination symmetry to permutations.
Exam Tip
Permutation में complement symmetry नहीं होती और length बदलने से count बदलता है। परीक्षा में combination symmetry को permutation पर न लगाएं।
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