\(\sum_{r=0}^{n}r{}^{n}C_r=n2^{n-1}\) में दाईं ओर \(2^{n-1}\) क्यों आता है?
Why does \(2^{n-1}\) appear on the right side of \(\sum_{r=0}^{n}r{}^{n}C_r=n2^{n-1}\)?
Explanation opens after your attempt
A. marked member चुनने के बाद बाकी (n-1) members स्वतंत्र रूप से चुने या छोड़े जाते हैंAfter choosing the marked member, the remaining (n-1) members are freely chosen or left
Concept
There are (n) choices for the marked member and two choices for each remaining member. In exams connect the extra (r) in binomial sums with marking.
Why this answer is correct
The correct answer is A. marked member चुनने के बाद बाकी (n-1) members स्वतंत्र रूप से चुने या छोड़े जाते हैं / After choosing the marked member, the remaining (n-1) members are freely chosen or left. There are (n) choices for the marked member and two choices for each remaining member. In exams connect the extra (r) in binomial sums with marking.
Exam Tip
पहले marked member के (n) choices हैं और बाकी पर two choices हैं। परीक्षा में binomial sum में extra (r) को marking से जोड़ें।
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