असमानता \( \frac{3x-2}{5}-\frac{x+4}{2}\geq -1 \) का हल कौन-सा है?

Which is the solution of the inequality \( \frac{3x-2}{5}-\frac{x+4}{2}\geq -1 \)?

Explanation opens after your attempt
Correct Answer

B. \(x\geq 14\)

Step 1

Concept

Multiplying by (10) gives \(6x-4-5x-20\geq -10\). Therefore \(x\geq 14\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(x\geq 14\). Multiplying by (10) gives \(6x-4-5x-20\geq -10\). Therefore \(x\geq 14\) is correct.

Step 3

Exam Tip

(10) से गुणा करने पर \(6x-4-5x-20\geq -10\) मिलता है। इसलिए \(x\geq 14\) सही है।

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Mathematics Answer, Explanation and Revision Hints

असमानता \( \frac{3x-2}{5}-\frac{x+4}{2}\geq -1 \) का हल कौन-सा है? / Which is the solution of the inequality \( \frac{3x-2}{5}-\frac{x+4}{2}\geq -1 \)?

Correct Answer: B. \(x\geq 14\). Explanation: (10) से गुणा करने पर \(6x-4-5x-20\geq -10\) मिलता है। इसलिए \(x\geq 14\) सही है। / Multiplying by (10) gives \(6x-4-5x-20\geq -10\). Therefore \(x\geq 14\) is correct.

Which concept should I revise for this Mathematics MCQ?

Multiplying by (10) gives \(6x-4-5x-20\geq -10\). Therefore \(x\geq 14\) is correct.

What exam hint can help solve this Mathematics question?

(10) से गुणा करने पर \(6x-4-5x-20\geq -10\) मिलता है। इसलिए \(x\geq 14\) सही है।