\(\sum_{r=0}^{n}r{}^{n}C_r=n2^{n-1}\) किस double counting से आता है?
Which double counting gives \(\sum_{r=0}^{n}r{}^{n}C_r=n2^{n-1}\)?
Explanation opens after your attempt
A. एक selected सदस्य को mark करनाMarking one selected member
Concept
Choose a subset and mark one member, or first choose the marked member and freely choose the rest. In exams treat the factor (r) as a marked choice.
Why this answer is correct
The correct answer is A. एक selected सदस्य को mark करना / Marking one selected member. Choose a subset and mark one member, or first choose the marked member and freely choose the rest. In exams treat the factor (r) as a marked choice.
Exam Tip
पहले subset चुनकर उसमें एक member mark करें या पहले marked member चुनकर बाकी freely चुनें। परीक्षा में (r) factor को marked choice समझें।
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