ग्राफ \(y=\sqrt{x+1}\) और (y=x-1) के प्रतिच्छेद का (x)-मान क्या है?

What is the (x)-value of the intersection of the graphs \(y=\sqrt{x+1}\) and (y=x-1)?

Explanation opens after your attempt
Correct Answer

C. (x=3)

Step 1

Concept

In \(\sqrt{x+1}=x-1\), \(x\ge1\), and at (x=3) both sides are (2). In exams, the right side must be non-negative before squaring.

Step 2

Why this answer is correct

The correct answer is C. (x=3). In \(\sqrt{x+1}=x-1\), \(x\ge1\), and at (x=3) both sides are (2). In exams, the right side must be non-negative before squaring.

Step 3

Exam Tip

\(\sqrt{x+1}=x-1\) में \(x\ge1\) और (x=3) रखने पर दोनों (2) हैं। परीक्षा में वर्ग करने से पहले दाईं ओर अनऋणात्मक होनी चाहिए।

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Mathematics Answer, Explanation and Revision Hints

ग्राफ \(y=\sqrt{x+1}\) और (y=x-1) के प्रतिच्छेद का (x)-मान क्या है? / What is the (x)-value of the intersection of the graphs \(y=\sqrt{x+1}\) and (y=x-1)?

Correct Answer: C. (x=3). Explanation: \(\sqrt{x+1}=x-1\) में \(x\ge1\) और (x=3) रखने पर दोनों (2) हैं। परीक्षा में वर्ग करने से पहले दाईं ओर अनऋणात्मक होनी चाहिए। / In \(\sqrt{x+1}=x-1\), \(x\ge1\), and at (x=3) both sides are (2). In exams, the right side must be non-negative before squaring.

Which concept should I revise for this Mathematics MCQ?

In \(\sqrt{x+1}=x-1\), \(x\ge1\), and at (x=3) both sides are (2). In exams, the right side must be non-negative before squaring.

What exam hint can help solve this Mathematics question?

\(\sqrt{x+1}=x-1\) में \(x\ge1\) और (x=3) रखने पर दोनों (2) हैं। परीक्षा में वर्ग करने से पहले दाईं ओर अनऋणात्मक होनी चाहिए।