असमानता (\frac{2}{5}(5x-3)-\frac{1}{4}(8x+4)<\frac{5}{2}) का हल समुच्चय क्या है?

What is the solution set of (\frac{2}{5}(5x-3)-\frac{1}{4}(8x+4)<\frac{5}{2})?

Explanation opens after your attempt
Correct Answer

C. \(x\in\mathbb{R}\)

Step 1

Concept

The left side becomes \(-\frac{11}{5}\), and \(-\frac{11}{5}<\frac{5}{2}\) is true. Therefore every real (x) is a solution.

Step 2

Why this answer is correct

The correct answer is C. \(x\in\mathbb{R}\). The left side becomes \(-\frac{11}{5}\), and \(-\frac{11}{5}<\frac{5}{2}\) is true. Therefore every real (x) is a solution.

Step 3

Exam Tip

बायाँ पक्ष \(-\frac{11}{5}\) बनता है और \(-\frac{11}{5}<\frac{5}{2}\) सत्य है। इसलिए हर वास्तविक (x) हल है।

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Mathematics Answer, Explanation and Revision Hints

असमानता (\frac{2}{5}(5x-3)-\frac{1}{4}(8x+4)<\frac{5}{2}) का हल समुच्चय क्या है? / What is the solution set of (\frac{2}{5}(5x-3)-\frac{1}{4}(8x+4)<\frac{5}{2})?

Correct Answer: C. \(x\in\mathbb{R}\). Explanation: बायाँ पक्ष \(-\frac{11}{5}\) बनता है और \(-\frac{11}{5}<\frac{5}{2}\) सत्य है। इसलिए हर वास्तविक (x) हल है। / The left side becomes \(-\frac{11}{5}\), and \(-\frac{11}{5}<\frac{5}{2}\) is true. Therefore every real (x) is a solution.

Which concept should I revise for this Mathematics MCQ?

The left side becomes \(-\frac{11}{5}\), and \(-\frac{11}{5}<\frac{5}{2}\) is true. Therefore every real (x) is a solution.

What exam hint can help solve this Mathematics question?

बायाँ पक्ष \(-\frac{11}{5}\) बनता है और \(-\frac{11}{5}<\frac{5}{2}\) सत्य है। इसलिए हर वास्तविक (x) हल है।