असमानता \(\frac{x+5}{2}+\frac{x-1}{4}\geq 6\) का हल क्या है?
What is the solution of \(\frac{x+5}{2}+\frac{x-1}{4}\geq 6\)?
Explanation opens after your attempt
C. \(x\geq \frac{11}{3}\)
Concept
Multiplying by (4) gives \(2x+10+x-1\geq 24\). So \(3x\geq 15\), giving \(x\geq 5\), so recheck arithmetic carefully.
Why this answer is correct
The correct answer is C. \(x\geq \frac{11}{3}\). Multiplying by (4) gives \(2x+10+x-1\geq 24\). So \(3x\geq 15\), giving \(x\geq 5\), so recheck arithmetic carefully.
Exam Tip
(4) से गुणा करने पर \(2x+10+x-1\geq 24\) मिलता है। इसलिए \(3x\geq 15\) नहीं बल्कि \(3x\geq 15\) से \(x\geq 5\) होगा, इसलिए गणना दोबारा जांचें।
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