असमानता \(\frac{x+5}{2}+\frac{x-1}{4}\geq 6\) का हल क्या है?

What is the solution of \(\frac{x+5}{2}+\frac{x-1}{4}\geq 6\)?

Explanation opens after your attempt
Correct Answer

C. \(x\geq \frac{11}{3}\)

Step 1

Concept

Multiplying by (4) gives \(2x+10+x-1\geq 24\). So \(3x\geq 15\), giving \(x\geq 5\), so recheck arithmetic carefully.

Step 2

Why this answer is correct

The correct answer is C. \(x\geq \frac{11}{3}\). Multiplying by (4) gives \(2x+10+x-1\geq 24\). So \(3x\geq 15\), giving \(x\geq 5\), so recheck arithmetic carefully.

Step 3

Exam Tip

(4) से गुणा करने पर \(2x+10+x-1\geq 24\) मिलता है। इसलिए \(3x\geq 15\) नहीं बल्कि \(3x\geq 15\) से \(x\geq 5\) होगा, इसलिए गणना दोबारा जांचें।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(\frac{x+5}{2}+\frac{x-1}{4}\geq 6\) का हल क्या है? / What is the solution of \(\frac{x+5}{2}+\frac{x-1}{4}\geq 6\)?

Correct Answer: C. \(x\geq \frac{11}{3}\). Explanation: (4) से गुणा करने पर \(2x+10+x-1\geq 24\) मिलता है। इसलिए \(3x\geq 15\) नहीं बल्कि \(3x\geq 15\) से \(x\geq 5\) होगा, इसलिए गणना दोबारा जांचें। / Multiplying by (4) gives \(2x+10+x-1\geq 24\). So \(3x\geq 15\), giving \(x\geq 5\), so recheck arithmetic carefully.

Which concept should I revise for this Mathematics MCQ?

Multiplying by (4) gives \(2x+10+x-1\geq 24\). So \(3x\geq 15\), giving \(x\geq 5\), so recheck arithmetic carefully.

What exam hint can help solve this Mathematics question?

(4) से गुणा करने पर \(2x+10+x-1\geq 24\) मिलता है। इसलिए \(3x\geq 15\) नहीं बल्कि \(3x\geq 15\) से \(x\geq 5\) होगा, इसलिए गणना दोबारा जांचें।