असमानता \(\frac{x-1}{2}+\frac{x-2}{3}+\frac{x-3}{6}\ge 4\) का हल क्या है?
What is the solution of \(\frac{x-1}{2}+\frac{x-2}{3}+\frac{x-3}{6}\ge 4\)?
Explanation opens after your attempt
Correct Answer
A. \(x\ge \frac{17}{3}\)
Concept
Clearing denominators gives \(6x-10\ge 24\). Hence \(x\ge \frac{17}{3}\) is the solution.
Why this answer is correct
The correct answer is A. \(x\ge \frac{17}{3}\). Clearing denominators gives \(6x-10\ge 24\). Hence \(x\ge \frac{17}{3}\) is the solution.
Exam Tip
हर हटाने पर \(6x-10\ge 24\) मिलता है। अतः \(x\ge \frac{17}{3}\) हल है।
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