असमानता \(\frac{7-2x}{5}\le\frac{3x+1}{10}\) का हल क्या है?
What is the solution of \(\frac{7-2x}{5}\le\frac{3x+1}{10}\)?
Explanation opens after your attempt
Correct Answer
A. \(x\ge\frac{13}{7}\)
Concept
Multiplying by positive (10) gives \(14-4x\le3x+1\). Thus \(13\le7x\), so \(x\ge\frac{13}{7}\).
Why this answer is correct
The correct answer is A. \(x\ge\frac{13}{7}\). Multiplying by positive (10) gives \(14-4x\le3x+1\). Thus \(13\le7x\), so \(x\ge\frac{13}{7}\).
Exam Tip
धनात्मक (10) से गुणा करने पर \(14-4x\le3x+1\) मिलता है। इससे \(13\le7x\), अतः \(x\ge\frac{13}{7}\)।
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