क्षेत्र \(x\le 4\), \(y\le 3\), \(x+y\ge 2\) बिना \(x\ge 0\), \(y\ge 0\) शर्तों के कैसा होगा?

What is the region \(x\le 4\), \(y\le 3\), \(x+y\ge 2\) without the conditions \(x\ge 0\), \(y\ge 0\)?

Explanation opens after your attempt
Correct Answer

B. असीमUnbounded

Step 1

Concept

There are upper and right bounds, but the region can extend indefinitely toward the lower-left direction. To test boundedness, check restrictions in every direction.

Step 2

Why this answer is correct

The correct answer is B. असीम / Unbounded. There are upper and right bounds, but the region can extend indefinitely toward the lower-left direction. To test boundedness, check restrictions in every direction.

Step 3

Exam Tip

ऊपर और दाईं ओर सीमाएं हैं, पर बाईं-नीचे दिशा में क्षेत्र अनंत तक जा सकता है। सीमितता जांचते समय सभी दिशाओं में रोक देखें।

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Mathematics Answer, Explanation and Revision Hints

क्षेत्र \(x\le 4\), \(y\le 3\), \(x+y\ge 2\) बिना \(x\ge 0\), \(y\ge 0\) शर्तों के कैसा होगा? / What is the region \(x\le 4\), \(y\le 3\), \(x+y\ge 2\) without the conditions \(x\ge 0\), \(y\ge 0\)?

Correct Answer: B. असीम / Unbounded. Explanation: ऊपर और दाईं ओर सीमाएं हैं, पर बाईं-नीचे दिशा में क्षेत्र अनंत तक जा सकता है। सीमितता जांचते समय सभी दिशाओं में रोक देखें। / There are upper and right bounds, but the region can extend indefinitely toward the lower-left direction. To test boundedness, check restrictions in every direction.

Which concept should I revise for this Mathematics MCQ?

There are upper and right bounds, but the region can extend indefinitely toward the lower-left direction. To test boundedness, check restrictions in every direction.

What exam hint can help solve this Mathematics question?

ऊपर और दाईं ओर सीमाएं हैं, पर बाईं-नीचे दिशा में क्षेत्र अनंत तक जा सकता है। सीमितता जांचते समय सभी दिशाओं में रोक देखें।