फलन (f(x)=\frac{1}{x-2}) का परिसर क्या है?

What is the range of (f(x)=\frac{1}{x-2})?

Explanation opens after your attempt
Correct Answer

A. (\(0,\infty\))

Step 1

Concept

When \(x \ne 0\), \(x^2>0\), so \(\frac{1}{x^2}>0\). The value (0) is never obtained.

Step 2

Why this answer is correct

The correct answer is A. (\(0,\infty\)). When \(x \ne 0\), \(x^2>0\), so \(\frac{1}{x^2}>0\). The value (0) is never obtained.

Step 3

Exam Tip

\(x \ne 0\) होने पर \(x^2>0\), इसलिए \(\frac{1}{x^2}>0\) है। मान (0) कभी नहीं मिलता।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{1}{x-2}) का परिसर क्या है? / What is the range of (f(x)=\frac{1}{x-2})?

Correct Answer: A. (\(0,\infty\)). Explanation: \(x \ne 0\) होने पर \(x^2>0\), इसलिए \(\frac{1}{x^2}>0\) है। मान (0) कभी नहीं मिलता। / When \(x \ne 0\), \(x^2>0\), so \(\frac{1}{x^2}>0\). The value (0) is never obtained.

Which concept should I revise for this Mathematics MCQ?

When \(x \ne 0\), \(x^2>0\), so \(\frac{1}{x^2}>0\). The value (0) is never obtained.

What exam hint can help solve this Mathematics question?

\(x \ne 0\) होने पर \(x^2>0\), इसलिए \(\frac{1}{x^2}>0\) है। मान (0) कभी नहीं मिलता।