\(r{}^{n}C_r=n{}^{n-1}C_{r-1}\) की double counting व्याख्या क्या है?

What is the double-counting interpretation of \(r{}^{n}C_r=n{}^{n-1}C_{r-1}\)?

Explanation opens after your attempt
Correct Answer

A. एक चुने हुए (r)-समूह में एक सदस्य को चिह्नित करनाMarking one member in a chosen (r)-group

Step 1

Concept

The left side chooses a group and marks one member, while the right side chooses the marked member first. In exams treat the factor (r) as a marked choice.

Step 2

Why this answer is correct

The correct answer is A. एक चुने हुए (r)-समूह में एक सदस्य को चिह्नित करना / Marking one member in a chosen (r)-group. The left side chooses a group and marks one member, while the right side chooses the marked member first. In exams treat the factor (r) as a marked choice.

Step 3

Exam Tip

बाईं ओर समूह चुनकर mark करते हैं, दाईं ओर marked member पहले चुनते हैं। परीक्षा में (r) factor को marked choice मानें।

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Mathematics Answer, Explanation and Revision Hints

\(r{}^{n}C_r=n{}^{n-1}C_{r-1}\) की double counting व्याख्या क्या है? / What is the double-counting interpretation of \(r{}^{n}C_r=n{}^{n-1}C_{r-1}\)?

Correct Answer: A. एक चुने हुए (r)-समूह में एक सदस्य को चिह्नित करना / Marking one member in a chosen (r)-group. Explanation: बाईं ओर समूह चुनकर mark करते हैं, दाईं ओर marked member पहले चुनते हैं। परीक्षा में (r) factor को marked choice मानें। / The left side chooses a group and marks one member, while the right side chooses the marked member first. In exams treat the factor (r) as a marked choice.

Which concept should I revise for this Mathematics MCQ?

The left side chooses a group and marks one member, while the right side chooses the marked member first. In exams treat the factor (r) as a marked choice.

What exam hint can help solve this Mathematics question?

बाईं ओर समूह चुनकर mark करते हैं, दाईं ओर marked member पहले चुनते हैं। परीक्षा में (r) factor को marked choice मानें।