\(\sum_{r=0}^{n}r^2{}^{n}C_r\) का सही रूप क्या है?

What is the correct form of \(\sum_{r=0}^{n}r^2{}^{n}C_r\)?

Explanation opens after your attempt
Correct Answer

C. (n(n+1)2^{n-2})

Step 1

Concept

Write (r-2=r(r-1)+r) and add two standard sums. In exams splitting \(r^2\) is the fastest method.

Step 2

Why this answer is correct

The correct answer is C. (n(n+1)2^{n-2}). Write (r-2=r(r-1)+r) and add two standard sums. In exams splitting \(r^2\) is the fastest method.

Step 3

Exam Tip

(r-2=r(r-1)+r) लिखकर दो standard sums जोड़ते हैं। परीक्षा में \(r^2\) को split करना तेज तरीका है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\sum_{r=0}^{n}r^2{}^{n}C_r\) का सही रूप क्या है? / What is the correct form of \(\sum_{r=0}^{n}r^2{}^{n}C_r\)?

Correct Answer: C. (n(n+1)2^{n-2}). Explanation: (r-2=r(r-1)+r) लिखकर दो standard sums जोड़ते हैं। परीक्षा में \(r^2\) को split करना तेज तरीका है। / Write (r-2=r(r-1)+r) and add two standard sums. In exams splitting \(r^2\) is the fastest method.

Which concept should I revise for this Mathematics MCQ?

Write (r-2=r(r-1)+r) and add two standard sums. In exams splitting \(r^2\) is the fastest method.

What exam hint can help solve this Mathematics question?

(r-2=r(r-1)+r) लिखकर दो standard sums जोड़ते हैं। परीक्षा में \(r^2\) को split करना तेज तरीका है।