Class 11 Mathematics Permutations and Combinations Derivations of formulas and their connections Hard Level 65

किस condition में repeated objects arrangement का सूत्र \(\frac{n!}{p!q!}\) लागू होगा?

Under which condition does the repeated-object arrangement formula \(\frac{n!}{p!q!}\) apply?

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Correct Answer

A. (n) objects में (p) एक प्रकार के और (q) दूसरे प्रकार के identical होंAmong (n) objects, (p) of one type and (q) of another type are identical

Step 1

Concept

Internal permutations of same-type objects do not create new arrangements. In exams derive repeated-letter counts using factorial division.

Step 2

Why this answer is correct

The correct answer is A. (n) objects में (p) एक प्रकार के और (q) दूसरे प्रकार के identical हों / Among (n) objects, (p) of one type and (q) of another type are identical. Internal permutations of same-type objects do not create new arrangements. In exams derive repeated-letter counts using factorial division.

Step 3

Exam Tip

Same-type objects की internal permutations नई arrangement नहीं देतीं। परीक्षा में repeated letters की count को factorial division से derive करें।

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किस condition में repeated objects arrangement का सूत्र \(\frac{n!}{p!q!}\) लागू होगा? / Under which condition does the repeated-object arrangement formula \(\frac{n!}{p!q!}\) apply?

Correct Answer: A. (n) objects में (p) एक प्रकार के और (q) दूसरे प्रकार के identical हों / Among (n) objects, (p) of one type and (q) of another type are identical. Explanation: Same-type objects की internal permutations नई arrangement नहीं देतीं। परीक्षा में repeated letters की count को factorial division से derive करें। / Internal permutations of same-type objects do not create new arrangements. In exams derive repeated-letter counts using factorial division.

Which concept should I revise for this Mathematics MCQ?

Internal permutations of same-type objects do not create new arrangements. In exams derive repeated-letter counts using factorial division.

What exam hint can help solve this Mathematics question?

Same-type objects की internal permutations नई arrangement नहीं देतीं। परीक्षा में repeated letters की count को factorial division से derive करें।