(\sum_{r=0}^{n} (-1)^r{}^{n}C_r=0) किस substitution से जुड़ा है?
The identity (\sum_{r=0}^{n} (-1)^r{}^{n}C_r=0) is connected with which substitution?
Explanation opens after your attempt
C. ((1+x)^n) में (x=-1)(x=-1) in ((1+x)^n)
Concept
Putting (x=-1) gives ((1-1)^n=0). In exams think of (x=-1) for alternating binomial sums.
Why this answer is correct
The correct answer is C. ((1+x)^n) में (x=-1) / (x=-1) in ((1+x)^n). Putting (x=-1) gives ((1-1)^n=0). In exams think of (x=-1) for alternating binomial sums.
Exam Tip
(x=-1) रखने पर ((1-1)^n=0) मिलता है। परीक्षा में alternating binomial sum में (x=-1) सोचें।
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