(D_n=n!\left(1-\frac{1}{1!}+\frac{1}{2!}-\cdots+(-1)^n\frac{1}{n!}\right)) किस principle से आता है?

The formula (D_n=n!\left(1-\frac{1}{1!}+\frac{1}{2!}-\cdots+(-1)^n\frac{1}{n!}\right)) comes from which principle?

Explanation opens after your attempt
Correct Answer

A. Inclusion-exclusion

Step 1

Concept

Permutations with fixed points are subtracted and added alternately. In exams think of inclusion-exclusion when no object is in its correct place.

Step 2

Why this answer is correct

The correct answer is A. Inclusion-exclusion. Permutations with fixed points are subtracted and added alternately. In exams think of inclusion-exclusion when no object is in its correct place.

Step 3

Exam Tip

Fixed points वाले permutations को alternating तरीके से घटाया और जोड़ा जाता है। परीक्षा में कोई object सही स्थान पर न हो तो inclusion-exclusion सोचें।

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Mathematics Answer, Explanation and Revision Hints

(D_n=n!\left(1-\frac{1}{1!}+\frac{1}{2!}-\cdots+(-1)^n\frac{1}{n!}\right)) किस principle से आता है? / The formula (D_n=n!\left(1-\frac{1}{1!}+\frac{1}{2!}-\cdots+(-1)^n\frac{1}{n!}\right)) comes from which principle?

Correct Answer: A. Inclusion-exclusion. Explanation: Fixed points वाले permutations को alternating तरीके से घटाया और जोड़ा जाता है। परीक्षा में कोई object सही स्थान पर न हो तो inclusion-exclusion सोचें। / Permutations with fixed points are subtracted and added alternately. In exams think of inclusion-exclusion when no object is in its correct place.

Which concept should I revise for this Mathematics MCQ?

Permutations with fixed points are subtracted and added alternately. In exams think of inclusion-exclusion when no object is in its correct place.

What exam hint can help solve this Mathematics question?

Fixed points वाले permutations को alternating तरीके से घटाया और जोड़ा जाता है। परीक्षा में कोई object सही स्थान पर न हो तो inclusion-exclusion सोचें।