\({}^{n+r-1}C_r\) और \({}^{n+r-1}C_{n-1}\) का equality किस identity से आती है?

The equality of \({}^{n+r-1}C_r\) and \({}^{n+r-1}C_{n-1}\) comes from which identity?

Explanation opens after your attempt
Correct Answer

B. Complement identity

Step 1

Concept

The two lower indices sum to (n+r-1). In exams accept complementary forms in stars and bars answers.

Step 2

Why this answer is correct

The correct answer is B. Complement identity. The two lower indices sum to (n+r-1). In exams accept complementary forms in stars and bars answers.

Step 3

Exam Tip

दोनों lower indices का sum (n+r-1) है। परीक्षा में stars and bars answers में complementary forms accept करें।

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\({}^{n+r-1}C_r\) और \({}^{n+r-1}C_{n-1}\) का equality किस identity से आती है? / The equality of \({}^{n+r-1}C_r\) and \({}^{n+r-1}C_{n-1}\) comes from which identity?

Correct Answer: B. Complement identity. Explanation: दोनों lower indices का sum (n+r-1) है। परीक्षा में stars and bars answers में complementary forms accept करें। / The two lower indices sum to (n+r-1). In exams accept complementary forms in stars and bars answers.

Which concept should I revise for this Mathematics MCQ?

The two lower indices sum to (n+r-1). In exams accept complementary forms in stars and bars answers.

What exam hint can help solve this Mathematics question?

दोनों lower indices का sum (n+r-1) है। परीक्षा में stars and bars answers में complementary forms accept करें।