असमानता (4(x-2)-3(2-x)\ge 5x+1) को हल कीजिए।

Solve the inequality (4(x-2)-3(2-x)\ge 5x+1).

Explanation opens after your attempt
Correct Answer

B. \(x\ge \frac{15}{2}\)

Step 1

Concept

Simplification gives \(2x\ge 15\), so \(x\ge \frac{15}{2}\). Apply the negative sign carefully while opening brackets.

Step 2

Why this answer is correct

The correct answer is B. \(x\ge \frac{15}{2}\). Simplification gives \(2x\ge 15\), so \(x\ge \frac{15}{2}\). Apply the negative sign carefully while opening brackets.

Step 3

Exam Tip

सरलीकरण से \(2x\ge 15\) मिलता है, इसलिए \(x\ge \frac{15}{2}\)। कोष्ठक खोलते समय ऋण चिह्न ध्यान से लगाएँ।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता (4(x-2)-3(2-x)\ge 5x+1) को हल कीजिए। / Solve the inequality (4(x-2)-3(2-x)\ge 5x+1).

Correct Answer: B. \(x\ge \frac{15}{2}\). Explanation: सरलीकरण से \(2x\ge 15\) मिलता है, इसलिए \(x\ge \frac{15}{2}\)। कोष्ठक खोलते समय ऋण चिह्न ध्यान से लगाएँ। / Simplification gives \(2x\ge 15\), so \(x\ge \frac{15}{2}\). Apply the negative sign carefully while opening brackets.

Which concept should I revise for this Mathematics MCQ?

Simplification gives \(2x\ge 15\), so \(x\ge \frac{15}{2}\). Apply the negative sign carefully while opening brackets.

What exam hint can help solve this Mathematics question?

सरलीकरण से \(2x\ge 15\) मिलता है, इसलिए \(x\ge \frac{15}{2}\)। कोष्ठक खोलते समय ऋण चिह्न ध्यान से लगाएँ।