\( \frac{15\pi}{2} \) रेडियन की अंतिम भुजा किस अक्ष पर होगी?
On which axis will the terminal side of \( \frac{15\pi}{2} \) radians lie?
Explanation opens after your attempt
D. ऋणात्मक (y)-अक्षNegative (y)-axis
Concept
\( \frac{15\pi}{2}-6\pi=\frac{3\pi}{2} \), and \( \frac{3\pi}{2} \) lies on the negative (y)-axis. Subtract multiples of \(2\pi\) to identify the axis.
Why this answer is correct
The correct answer is D. ऋणात्मक (y)-अक्ष / Negative (y)-axis. \( \frac{15\pi}{2}-6\pi=\frac{3\pi}{2} \), and \( \frac{3\pi}{2} \) lies on the negative (y)-axis. Subtract multiples of \(2\pi\) to identify the axis.
Exam Tip
\( \frac{15\pi}{2}-6\pi=\frac{3\pi}{2} \) है और \( \frac{3\pi}{2} \) ऋणात्मक (y)-अक्ष पर है। \(2\pi\) के गुणज घटाकर अक्ष पहचानें।
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