किस अंतराल में \( -\frac{23\pi}{10} \) का मुख्य सहसमापी कोण स्थित है?
In which interval does the principal coterminal angle of \( -\frac{23\pi}{10} \) lie?
Explanation opens after your attempt
Correct Answer
D. \( \frac{3\pi}{2}<\theta<2\pi \)
Concept
\( -\frac{23\pi}{10}+\frac{40\pi}{10}=\frac{17\pi}{10} \), which lies between \( \frac{3\pi}{2} \) and \(2\pi\). First find the principal angle.
Why this answer is correct
The correct answer is D. \( \frac{3\pi}{2}<\theta<2\pi \). \( -\frac{23\pi}{10}+\frac{40\pi}{10}=\frac{17\pi}{10} \), which lies between \( \frac{3\pi}{2} \) and \(2\pi\). First find the principal angle.
Exam Tip
\( -\frac{23\pi}{10}+\frac{40\pi}{10}=\frac{17\pi}{10} \) है जो \( \frac{3\pi}{2} \) और \(2\pi\) के बीच है। पहले मुख्य कोण निकालें।
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