यदि \(x\in\mathbb{R}\), तो (5x-2<3x+10) और \(x+4\ge2\) का संयुक्त हल क्या है?
If \(x\in\mathbb{R}\), what is the combined solution of (5x-2<3x+10) and \(x+4\ge2\)?
Explanation opens after your attempt
Correct Answer
A. \(-2\le x<6\)
Concept
The first inequality gives (x<6), and the second gives \(x\ge-2\). Their intersection is \(-2\le x<6\).
Why this answer is correct
The correct answer is A. \(-2\le x<6\). The first inequality gives (x<6), and the second gives \(x\ge-2\). Their intersection is \(-2\le x<6\).
Exam Tip
पहली असमानता (x<6) देती है और दूसरी \(x\ge-2\) देती है। दोनों का प्रतिच्छेद \(-2\le x<6\) है।
Login to save your score, XP, coins and progress.