\(यदि (U={x:x \in \mathbb{N},\ 1\le x\le 30}) और (A={x:x \in U,\ x\) 2 और 3 दोनों से विभाज्य है\(}), तो (n(A^{c})) क्या है\)?

\(If (U={x:x \in \mathbb{N},\ 1\le x\le 30}) and (A={x:x \in U,\ x\) is divisible by both 2 and \(3}), what is (n(A^{c}))\)?

Explanation opens after your attempt
Correct Answer

B. (25)

Step 1

Concept

Numbers divisible by both (2) and (3) are multiples of (6), giving (5) numbers. Thus (n\(A^{c}\)=30-5=25).

Step 2

Why this answer is correct

The correct answer is B. (25). Numbers divisible by both (2) and (3) are multiples of (6), giving (5) numbers. Thus (n\(A^{c}\)=30-5=25).

Step 3

Exam Tip

(2) और (3) दोनों से विभाज्य संख्याएं (6) के गुणज हैं, यानी (5) संख्याएं। इसलिए (n\(A^{c}\)=30-5=25)।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (U={x:x \in \mathbb{N},\ 1\le x\le 30}) और (A={x:x \in U,\ x\) 2 और 3 दोनों से विभाज्य है}), तो (n\(A^{c}\)) क्या है? \(/ If (U={x:x \in \mathbb{N},\ 1\le x\le 30}) and (A={x:x \in U,\ x\) is divisible by both 2 and \(3}), what is (n(A^{c}))\)?

Correct Answer: B. (25). Explanation: (2) और (3) दोनों से विभाज्य संख्याएं (6) के गुणज हैं, यानी (5) संख्याएं। इसलिए (n\(A^{c}\)=30-5=25)। / Numbers divisible by both (2) and (3) are multiples of (6), giving (5) numbers. Thus (n\(A^{c}\)=30-5=25).

Which concept should I revise for this Mathematics MCQ?

Numbers divisible by both (2) and (3) are multiples of (6), giving (5) numbers. Thus (n\(A^{c}\)=30-5=25).

What exam hint can help solve this Mathematics question?

(2) और (3) दोनों से विभाज्य संख्याएं (6) के गुणज हैं, यानी (5) संख्याएं। इसलिए (n\(A^{c}\)=30-5=25)।