यदि \( \theta=\frac{14\pi}{5} \) है तो \( \theta-\pi \) का मुख्य सहसमापी कोण क्या है?
If \( \theta=\frac{14\pi}{5} \), what is the principal coterminal angle of \( \theta-\pi \)?
Explanation opens after your attempt
D. \( \frac{9\pi}{5} \)
Concept
\( \theta-\pi=\frac{14\pi}{5}-\frac{5\pi}{5}=\frac{9\pi}{5} \), and it is in (0) to \(2\pi\). First subtract and then check the range.
Why this answer is correct
The correct answer is D. \( \frac{9\pi}{5} \). \( \theta-\pi=\frac{14\pi}{5}-\frac{5\pi}{5}=\frac{9\pi}{5} \), and it is in (0) to \(2\pi\). First subtract and then check the range.
Exam Tip
\( \theta-\pi=\frac{14\pi}{5}-\frac{5\pi}{5}=\frac{9\pi}{5} \) है और यह (0) से \(2\pi\) में है। पहले घटाव करें फिर सीमा देखें।
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