यदि (p>0), तो (-p(4x+1)<2p(3-x)) का हल क्या है?

If (p>0), what is the solution of (-p(4x+1)<2p(3-x))?

Explanation opens after your attempt
Correct Answer

A. \(x>-\frac{7}{2}\)

Step 1

Concept

Dividing by positive (p) gives (-(4x+1)<6-2x). Thus (-2x<7), so \(x>-\frac{7}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(x>-\frac{7}{2}\). Dividing by positive (p) gives (-(4x+1)<6-2x). Thus (-2x<7), so \(x>-\frac{7}{2}\).

Step 3

Exam Tip

धनात्मक (p) से भाग देने पर (-(4x+1)<6-2x) मिलता है। इससे (-2x<7), इसलिए \(x>-\frac{7}{2}\)।

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Mathematics Answer, Explanation and Revision Hints

यदि (p>0), तो (-p(4x+1)<2p(3-x)) का हल क्या है? / If (p>0), what is the solution of (-p(4x+1)<2p(3-x))?

Correct Answer: A. \(x>-\frac{7}{2}\). Explanation: धनात्मक (p) से भाग देने पर (-(4x+1)<6-2x) मिलता है। इससे (-2x<7), इसलिए \(x>-\frac{7}{2}\)। / Dividing by positive (p) gives (-(4x+1)<6-2x). Thus (-2x<7), so \(x>-\frac{7}{2}\).

Which concept should I revise for this Mathematics MCQ?

Dividing by positive (p) gives (-(4x+1)<6-2x). Thus (-2x<7), so \(x>-\frac{7}{2}\).

What exam hint can help solve this Mathematics question?

धनात्मक (p) से भाग देने पर (-(4x+1)<6-2x) मिलता है। इससे (-2x<7), इसलिए \(x>-\frac{7}{2}\)।