Class 11 Mathematics Permutations and Combinations Derivations of formulas and their connections Hard Level 64

यदि (n) different objects को (p) और (q) groups में बांटा जाए जहां (p+q=n), तो count किस formula से जुड़ा है?

If (n) different objects are divided into groups of (p) and (q) where (p+q=n), the count is connected with which formula?

Explanation opens after your attempt
Correct Answer

A. \(\frac{n!}{p!q!}\)

Step 1

Concept

After choosing (p), the remaining (q) are fixed, so \(\frac{n!}{p!q!}\). In exams use factorial division for fixed group sizes.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{n!}{p!q!}\). After choosing (p), the remaining (q) are fixed, so \(\frac{n!}{p!q!}\). In exams use factorial division for fixed group sizes.

Step 3

Exam Tip

पहले (p) चुनने पर बाकी (q) तय हो जाते हैं, इसलिए \(\frac{n!}{p!q!}\)। परीक्षा में group sizes fixed हों तो factorial division सोचें।

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Mathematics Answer, Explanation and Revision Hints

यदि (n) different objects को (p) और (q) groups में बांटा जाए जहां (p+q=n), तो count किस formula से जुड़ा है? / If (n) different objects are divided into groups of (p) and (q) where (p+q=n), the count is connected with which formula?

Correct Answer: A. \(\frac{n!}{p!q!}\). Explanation: पहले (p) चुनने पर बाकी (q) तय हो जाते हैं, इसलिए \(\frac{n!}{p!q!}\)। परीक्षा में group sizes fixed हों तो factorial division सोचें। / After choosing (p), the remaining (q) are fixed, so \(\frac{n!}{p!q!}\). In exams use factorial division for fixed group sizes.

Which concept should I revise for this Mathematics MCQ?

After choosing (p), the remaining (q) are fixed, so \(\frac{n!}{p!q!}\). In exams use factorial division for fixed group sizes.

What exam hint can help solve this Mathematics question?

पहले (p) चुनने पर बाकी (q) तय हो जाते हैं, इसलिए \(\frac{n!}{p!q!}\)। परीक्षा में group sizes fixed हों तो factorial division सोचें।