यदि \(\frac{x-2}{3}\ge \frac{2x+1}{5}\) और \(x+4\le 10\), तो संयुक्त हल क्या है?
If \(\frac{x-2}{3}\ge \frac{2x+1}{5}\) and \(x+4\le 10\), what is the combined solution?
Explanation opens after your attempt
Correct Answer
B. \(x\le -13\)
Concept
The first inequality gives \(x\le -13\), and the second gives \(x\le 6\). Their intersection is \(x\le -13\).
Why this answer is correct
The correct answer is B. \(x\le -13\). The first inequality gives \(x\le -13\), and the second gives \(x\le 6\). Their intersection is \(x\le -13\).
Exam Tip
पहली असमानता से \(x\le -13\) और दूसरी से \(x\le 6\) मिलता है। दोनों का प्रतिच्छेद \(x\le -13\) है।
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