यदि \(-\frac{2x-1}{5}+\frac{x+4}{10}\ge \frac{3}{2}\), तो (x) का हल क्या है?
If \(-\frac{2x-1}{5}+\frac{x+4}{10}\ge \frac{3}{2}\), what is the solution for (x)?
Explanation opens after your attempt
Correct Answer
A. \(x\le -3\)
Concept
Clearing denominators gives (-2(2x-1)+(x+4)\ge15). Thus \(-3x\ge9\), so reversing the sign gives \(x\le-3\).
Why this answer is correct
The correct answer is A. \(x\le -3\). Clearing denominators gives (-2(2x-1)+(x+4)\ge15). Thus \(-3x\ge9\), so reversing the sign gives \(x\le-3\).
Exam Tip
हर हटाने पर (-2(2x-1)+(x+4)\ge15) मिलता है। इससे \(-3x\ge9\), इसलिए चिन्ह बदलकर \(x\le-3\) होगा।
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