यदि clockwise और anticlockwise arrangements को same माना जाए तो (n) अलग beads की necklace count किस रूप से जुड़ती है?
If clockwise and anticlockwise arrangements are considered same the necklace count of (n) distinct beads is connected with which form?
Explanation opens after your attempt
C. (\frac{(n-1)!}{2})
Concept
First removing rotations gives ((n-1)!) and then same reflection makes us divide by (2). In exams check both rotation and reflection in necklaces.
Why this answer is correct
The correct answer is C. (\frac{(n-1)!}{2}). First removing rotations gives ((n-1)!) and then same reflection makes us divide by (2). In exams check both rotation and reflection in necklaces.
Exam Tip
पहले rotations हटाकर ((n-1)!) मिलता है फिर reflection same होने से (2) से भाग देते हैं। परीक्षा में necklace में rotation और reflection दोनों देखें।
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