यदि \(A={x:x\in \mathbb{Z},x^2\le 4}\) और \(B=\{-1,0,1,3\}\) हैं, तो \(A\cap B\) क्या है?

If \(A={x:x\in \mathbb{Z},x^2\le 4}\) and \(B=\{-1,0,1,3\}\), what is \(A\cap B\)?

Explanation opens after your attempt
Correct Answer

B. ( {-1,0,1} )

Step 1

Concept

\(A=\{-2,-1,0,1,2\}\), so the common elements from (B) are (-1,0,1). In square conditions, also check negative integers.

Step 2

Why this answer is correct

The correct answer is B. ( {-1,0,1} ). \(A=\{-2,-1,0,1,2\}\), so the common elements from (B) are (-1,0,1). In square conditions, also check negative integers.

Step 3

Exam Tip

\(A=\{-2,-1,0,1,2\}\), इसलिए (B) से समान अवयव (-1,0,1) हैं। वर्ग वाली शर्त में ऋणात्मक पूर्णांक भी जांचें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\in \mathbb{Z},x^2\le 4}\) और \(B=\{-1,0,1,3\}\) हैं, तो \(A\cap B\) क्या है? / If \(A={x:x\in \mathbb{Z},x^2\le 4}\) and \(B=\{-1,0,1,3\}\), what is \(A\cap B\)?

Correct Answer: B. ( {-1,0,1} ). Explanation: \(A=\{-2,-1,0,1,2\}\), इसलिए (B) से समान अवयव (-1,0,1) हैं। वर्ग वाली शर्त में ऋणात्मक पूर्णांक भी जांचें। / \(A=\{-2,-1,0,1,2\}\), so the common elements from (B) are (-1,0,1). In square conditions, also check negative integers.

Which concept should I revise for this Mathematics MCQ?

\(A=\{-2,-1,0,1,2\}\), so the common elements from (B) are (-1,0,1). In square conditions, also check negative integers.

What exam hint can help solve this Mathematics question?

\(A=\{-2,-1,0,1,2\}\), इसलिए (B) से समान अवयव (-1,0,1) हैं। वर्ग वाली शर्त में ऋणात्मक पूर्णांक भी जांचें।