यदि \(A={x\in\mathbb{Z}: -7\le x\le 7}\), \(B={x\in\mathbb{Z}: x^2\le 16}\) और \(C={x\in\mathbb{Z}: 3\mid x}\) हैं, तो \((A-B)\cap C\) क्या है?
If \(A={x\in\mathbb{Z}: -7\le x\le 7}\), \(B={x\in\mathbb{Z}: x^2\le 16}\), and \(C={x\in\mathbb{Z}: 3\mid x}\), what is \((A-B)\cap C\)?
Explanation opens after your attempt
Correct Answer
A. ({-6,6})
Concept
\(B=\{-4,-3,-2,-1,0,1,2,3,4\}\), so (A-B={-7,-6,-5,5,6,7}). The elements divisible by (3) are ({-6,6}).
Why this answer is correct
The correct answer is A. ({-6,6}). \(B=\{-4,-3,-2,-1,0,1,2,3,4\}\), so (A-B={-7,-6,-5,5,6,7}). The elements divisible by (3) are ({-6,6}).
Exam Tip
\(B=\{-4,-3,-2,-1,0,1,2,3,4\}\) है, इसलिए (A-B={-7,-6,-5,5,6,7}) होगा। इनमें (3) से विभाज्य तत्व ({-6,6}) हैं।
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