यदि \(A={x\in\mathbb{Z}:-4\le x\le 6}\), \(B={x\in\mathbb{Z}:x^2\le16}\) और \(C={x\in\mathbb{Z}:2\mid x}\) हैं, तो (\(A\cap B\)-C) क्या है?
If \(A={x\in\mathbb{Z}:-4\le x\le 6}\), \(B={x\in\mathbb{Z}:x^2\le16}\), and \(C={x\in\mathbb{Z}:2\mid x}\), what is (\(A\cap B\)-C)?
Explanation opens after your attempt
Correct Answer
A. ({-3,-1,1,3})
Concept
\(A\cap B={-4,-3,-2,-1,0,1,2,3,4}\), and the even elements of (C) are removed. Hence the remaining odd elements are ({-3,-1,1,3}).
Why this answer is correct
The correct answer is A. ({-3,-1,1,3}). \(A\cap B={-4,-3,-2,-1,0,1,2,3,4}\), and the even elements of (C) are removed. Hence the remaining odd elements are ({-3,-1,1,3}).
Exam Tip
\(A\cap B={-4,-3,-2,-1,0,1,2,3,4}\) है और (C) के सम तत्व हटते हैं। इसलिए विषम तत्व ({-3,-1,1,3}) बचते हैं।
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