यदि (3(x-2)-2(x+4)\ge 5-\frac{x}{2}) है, तो (x) के लिए हल समुच्चय क्या है?
If (3(x-2)-2(x+4)\ge 5-\frac{x}{2}), what is the solution set for (x)?
Explanation opens after your attempt
Correct Answer
C. \({x:x\ge \frac{38}{3}}\)
Concept
The left side is (x-14), so \(x-14\ge 5-\frac{x}{2}\) gives \(\frac{3x}{2}\ge 19\) and \(x\ge \frac{38}{3}\). Sign errors while opening brackets are very common in exams.
Why this answer is correct
The correct answer is C. \({x:x\ge \frac{38}{3}}\). The left side is (x-14), so \(x-14\ge 5-\frac{x}{2}\) gives \(\frac{3x}{2}\ge 19\) and \(x\ge \frac{38}{3}\). Sign errors while opening brackets are very common in exams.
Exam Tip
बाईं ओर (x-14) है, इसलिए \(x-14\ge 5-\frac{x}{2}\) से \(\frac{3x}{2}\ge 19\) और \(x\ge \frac{38}{3}\) मिलता है। कोष्ठक खोलते समय संकेतों की गलती सबसे आम होती है।
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