(1) से (12) तक की संख्याओं में से (3) संख्याएं चुननी हैं जिनका योग विषम हो। कितने चयन संभव हैं?

Choose (3) numbers from (1) to (12) such that their sum is odd. How many selections are possible?

Explanation opens after your attempt
Correct Answer

B. (110)

Step 1

Concept

There are (6) odd and (6) even numbers. For odd sum choose (1) or (3) odd numbers, giving \(^{6}C_{1}{}^{6}C_{2}+^{6}C_{3}=110\).

Step 2

Why this answer is correct

The correct answer is B. (110). There are (6) odd and (6) even numbers. For odd sum choose (1) or (3) odd numbers, giving \(^{6}C_{1}{}^{6}C_{2}+^{6}C_{3}=110\).

Step 3

Exam Tip

(6) विषम और (6) सम संख्याएं हैं। विषम योग के लिए (1) या (3) विषम चुनें, संख्या \(^{6}C_{1}{}^{6}C_{2}+^{6}C_{3}=110\)।

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Mathematics Answer, Explanation and Revision Hints

(1) से (12) तक की संख्याओं में से (3) संख्याएं चुननी हैं जिनका योग विषम हो। कितने चयन संभव हैं? / Choose (3) numbers from (1) to (12) such that their sum is odd. How many selections are possible?

Correct Answer: B. (110). Explanation: (6) विषम और (6) सम संख्याएं हैं। विषम योग के लिए (1) या (3) विषम चुनें, संख्या \(^{6}C_{1}{}^{6}C_{2}+^{6}C_{3}=110\)। / There are (6) odd and (6) even numbers. For odd sum choose (1) or (3) odd numbers, giving \(^{6}C_{1}{}^{6}C_{2}+^{6}C_{3}=110\).

Which concept should I revise for this Mathematics MCQ?

There are (6) odd and (6) even numbers. For odd sum choose (1) or (3) odd numbers, giving \(^{6}C_{1}{}^{6}C_{2}+^{6}C_{3}=110\).

What exam hint can help solve this Mathematics question?

(6) विषम और (6) सम संख्याएं हैं। विषम योग के लिए (1) या (3) विषम चुनें, संख्या \(^{6}C_{1}{}^{6}C_{2}+^{6}C_{3}=110\)।