असमानताओं \(2x-y\leq 4\) और (2x-y>8) का संयुक्त हल-क्षेत्र कैसा है?

What is the common solution region of \(2x-y\leq 4\) and (2x-y>8)?

Explanation opens after your attempt
Correct Answer

C. खाली क्षेत्रEmpty region

Step 1

Concept

The same expression (2x-y) cannot be at most (4) and greater than (8) at the same time. Check contradictions before drawing the graph.

Step 2

Why this answer is correct

The correct answer is C. खाली क्षेत्र / Empty region. The same expression (2x-y) cannot be at most (4) and greater than (8) at the same time. Check contradictions before drawing the graph.

Step 3

Exam Tip

एक ही राशि (2x-y) एक साथ (4) से कम या बराबर और (8) से अधिक नहीं हो सकती। विरोधी शर्तें दिखें तो ग्राफ बनाने से पहले जांच लें।

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Mathematics Answer, Explanation and Revision Hints

असमानताओं \(2x-y\leq 4\) और (2x-y>8) का संयुक्त हल-क्षेत्र कैसा है? / What is the common solution region of \(2x-y\leq 4\) and (2x-y>8)?

Correct Answer: C. खाली क्षेत्र / Empty region. Explanation: एक ही राशि (2x-y) एक साथ (4) से कम या बराबर और (8) से अधिक नहीं हो सकती। विरोधी शर्तें दिखें तो ग्राफ बनाने से पहले जांच लें। / The same expression (2x-y) cannot be at most (4) and greater than (8) at the same time. Check contradictions before drawing the graph.

Which concept should I revise for this Mathematics MCQ?

The same expression (2x-y) cannot be at most (4) and greater than (8) at the same time. Check contradictions before drawing the graph.

What exam hint can help solve this Mathematics question?

एक ही राशि (2x-y) एक साथ (4) से कम या बराबर और (8) से अधिक नहीं हो सकती। विरोधी शर्तें दिखें तो ग्राफ बनाने से पहले जांच लें।