असमानताओं \(x+y\leq 6\), \(x+y\geq 6\), \(x-y\leq 2\), \(x-y\geq 2\) का संयुक्त हल कौन सा है?

What is the common solution of \(x+y\leq 6\), \(x+y\geq 6\), \(x-y\leq 2\), and \(x-y\geq 2\)?

Explanation opens after your attempt
Correct Answer

D. केवल बिंदु ((4,2))Only the point ((4,2))

Step 1

Concept

The first two conditions give (x+y=6), and the next two give (x-y=2). Their intersection is ((4,2)).

Step 2

Why this answer is correct

The correct answer is D. केवल बिंदु ((4,2)) / Only the point ((4,2)). The first two conditions give (x+y=6), and the next two give (x-y=2). Their intersection is ((4,2)).

Step 3

Exam Tip

पहली दो शर्तें (x+y=6) और अगली दो शर्तें (x-y=2) देती हैं। दोनों रेखाओं का प्रतिच्छेद ((4,2)) है।

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Mathematics Answer, Explanation and Revision Hints

असमानताओं \(x+y\leq 6\), \(x+y\geq 6\), \(x-y\leq 2\), \(x-y\geq 2\) का संयुक्त हल कौन सा है? / What is the common solution of \(x+y\leq 6\), \(x+y\geq 6\), \(x-y\leq 2\), and \(x-y\geq 2\)?

Correct Answer: D. केवल बिंदु ((4,2)) / Only the point ((4,2)). Explanation: पहली दो शर्तें (x+y=6) और अगली दो शर्तें (x-y=2) देती हैं। दोनों रेखाओं का प्रतिच्छेद ((4,2)) है। / The first two conditions give (x+y=6), and the next two give (x-y=2). Their intersection is ((4,2)).

Which concept should I revise for this Mathematics MCQ?

The first two conditions give (x+y=6), and the next two give (x-y=2). Their intersection is ((4,2)).

What exam hint can help solve this Mathematics question?

पहली दो शर्तें (x+y=6) और अगली दो शर्तें (x-y=2) देती हैं। दोनों रेखाओं का प्रतिच्छेद ((4,2)) है।