असमानताओं \(x+2y\leq 8\), \(x\geq 1\), \(y\geq 1\) के हल-क्षेत्र में (x) का अधिकतम मान क्या है?
In the solution region of \(x+2y\leq 8\), \(x\geq 1\), and \(y\geq 1\), what is the maximum value of (x)?
Explanation opens after your attempt
A. (6)
Concept
To maximize (x), take the minimum allowed value (y=1). Then \(x+2\leq 8\) gives \(x\leq 6\).
Why this answer is correct
The correct answer is A. (6). To maximize (x), take the minimum allowed value (y=1). Then \(x+2\leq 8\) gives \(x\leq 6\).
Exam Tip
(x) को अधिकतम करने के लिए (y) का न्यूनतम मान (1) लें। तब \(x+2\leq 8\) से \(x\leq 6\) मिलता है।
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