असमानताओं \(x+2y\leq 8\), \(x\geq 1\), \(y\geq 1\) के हल-क्षेत्र में (x) का अधिकतम मान क्या है?

In the solution region of \(x+2y\leq 8\), \(x\geq 1\), and \(y\geq 1\), what is the maximum value of (x)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

To maximize (x), take the minimum allowed value (y=1). Then \(x+2\leq 8\) gives \(x\leq 6\).

Step 2

Why this answer is correct

The correct answer is A. (6). To maximize (x), take the minimum allowed value (y=1). Then \(x+2\leq 8\) gives \(x\leq 6\).

Step 3

Exam Tip

(x) को अधिकतम करने के लिए (y) का न्यूनतम मान (1) लें। तब \(x+2\leq 8\) से \(x\leq 6\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

असमानताओं \(x+2y\leq 8\), \(x\geq 1\), \(y\geq 1\) के हल-क्षेत्र में (x) का अधिकतम मान क्या है? / In the solution region of \(x+2y\leq 8\), \(x\geq 1\), and \(y\geq 1\), what is the maximum value of (x)?

Correct Answer: A. (6). Explanation: (x) को अधिकतम करने के लिए (y) का न्यूनतम मान (1) लें। तब \(x+2\leq 8\) से \(x\leq 6\) मिलता है। / To maximize (x), take the minimum allowed value (y=1). Then \(x+2\leq 8\) gives \(x\leq 6\).

Which concept should I revise for this Mathematics MCQ?

To maximize (x), take the minimum allowed value (y=1). Then \(x+2\leq 8\) gives \(x\leq 6\).

What exam hint can help solve this Mathematics question?

(x) को अधिकतम करने के लिए (y) का न्यूनतम मान (1) लें। तब \(x+2\leq 8\) से \(x\leq 6\) मिलता है।