यदि \(A=\{1,2\}\) और \(B=\{a,b,c,d\}\) हैं, तो (A) से (B) तक कुल कितने संबंध हो सकते हैं?

If \(A=\{1,2\}\) and \(B=\{a,b,c,d\}\), how many relations can be formed from (A) to (B)?

Explanation opens after your attempt
Correct Answer

C. \(2^8\)

Step 1

Concept

Here (n\(A\times B\)=2\cdot4=8), so the number of relations is \(2^8\). Find (n\(A\times B\)) first.

Step 2

Why this answer is correct

The correct answer is C. \(2^8\). Here (n\(A\times B\)=2\cdot4=8), so the number of relations is \(2^8\). Find (n\(A\times B\)) first.

Step 3

Exam Tip

(n\(A\times B\)=2\cdot4=8), इसलिए संबंधों की संख्या \(2^8\) है। पहले (n\(A\times B\)) निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2\}\) और \(B=\{a,b,c,d\}\) हैं, तो (A) से (B) तक कुल कितने संबंध हो सकते हैं? / If \(A=\{1,2\}\) and \(B=\{a,b,c,d\}\), how many relations can be formed from (A) to (B)?

Correct Answer: C. \(2^8\). Explanation: (n\(A\times B\)=2\cdot4=8), इसलिए संबंधों की संख्या \(2^8\) है। पहले (n\(A\times B\)) निकालें। / Here (n\(A\times B\)=2\cdot4=8), so the number of relations is \(2^8\). Find (n\(A\times B\)) first.

Which concept should I revise for this Mathematics MCQ?

Here (n\(A\times B\)=2\cdot4=8), so the number of relations is \(2^8\). Find (n\(A\times B\)) first.

What exam hint can help solve this Mathematics question?

(n\(A\times B\)=2\cdot4=8), इसलिए संबंधों की संख्या \(2^8\) है। पहले (n\(A\times B\)) निकालें।