What volume of 2 mol L⁻¹ stock solution is needed to prepare 500 mL of 0.5 mol L⁻¹ solution?
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Answer and explanation
Correct answer: 125 mL
For dilution, M₁V₁ = M₂V₂. Taking the stock as M₁ = 2 mol L⁻¹ and the required solution as M₂ = 0.5 mol L⁻¹, V₁ = (0.5 × 500)/2 = 125 mL; the same volume unit can be used on both sides. Because the stock is four times as concentrated, one-fourth of the final volume is required.
Frequently asked questions
What is the correct answer to this question?
125 mL
Why is this the correct answer?
For dilution, M₁V₁ = M₂V₂. Taking the stock as M₁ = 2 mol L⁻¹ and the required solution as M₂ = 0.5 mol L⁻¹, V₁ = (0.5 × 500)/2 = 125 mL; the same volume unit can be used on both sides. Because the stock is four times as concentrated, one-fourth of the final volume is required.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
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