What is the approximate mole fraction of glucose in a 2 molal aqueous glucose solution?
Answer and explanation
Correct answer: 0.035
Molality means 2 mol glucose per 1 kg water. Taking the solvent mass as 1 kg, water contains 1000 ÷ 18 = 55.56 mol. The glucose mole fraction is x = 2/(2 + 55.56) = 0.03475, which rounds to 0.035. Option B is correct. The denominator must include both glucose and water moles, not water alone.
Frequently asked questions
What is the correct answer to this question?
0.035
Why is this the correct answer?
Molality means 2 mol glucose per 1 kg water. Taking the solvent mass as 1 kg, water contains 1000 ÷ 18 = 55.56 mol. The glucose mole fraction is x = 2/(2 + 55.56) = 0.03475, which rounds to 0.035. Option B is correct. The denominator must include both glucose and water moles, not water alone.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
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