If the partial pressure of a gas is doubled while temperature remains constant, what happens to its solubility in a liquid?
Answer and explanation
Correct answer: Solubility will become nearly double
At constant temperature, Henry's law gives x = p/KH, so the dissolved mole fraction x is directly proportional to the gas's partial pressure p when KH remains constant. Doubling p therefore doubles x in the idealised range, making the solubility approximately double. The result is described as nearly or ideally double because real systems can show deviations at extreme pressures or concentrations.
Frequently asked questions
What is the correct answer to this question?
Solubility will become nearly double
Why is this the correct answer?
At constant temperature, Henry's law gives x = p/KH, so the dissolved mole fraction x is directly proportional to the gas's partial pressure p when KH remains constant. Doubling p therefore doubles x in the idealised range, making the solubility approximately double. The result is described as nearly or ideally double because real systems can show deviations at extreme pressures or concentrations.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
