If the moles of solute remain the same and the mass of solvent is halved, what happens to molality?
Answer and explanation
Correct answer: It becomes double
Molality is defined by m = nsolute/kg solvent. Let the original quantity be n/m, where n is fixed solute moles and m is solvent mass. After halving the solvent mass, the value becomes n/(m/2) = 2n/m, which is twice the original molality. Therefore option B is correct. The numerator is unchanged while the denominator is reduced.
Frequently asked questions
What is the correct answer to this question?
It becomes double
Why is this the correct answer?
Molality is defined by m = nsolute/kg solvent. Let the original quantity be n/m, where n is fixed solute moles and m is solvent mass. After halving the solvent mass, the value becomes n/(m/2) = 2n/m, which is twice the original molality. Therefore option B is correct. The numerator is unchanged while the denominator is reduced.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
