If AB2 dissociates completely into A2+ and 2B− ions, what is the ideal value of the van’t Hoff factor, i?
Answer and explanation
Correct answer: 3
The van’t Hoff factor compares the total number of particles present after dissociation with the number of original formula units. One formula unit of AB2 produces one A2+ ion and two B− ions, making three particles in total. Under the stated assumption of complete and ideal dissociation, i = 3. No additional particles or association effects are included in this calculation.
Frequently asked questions
What is the correct answer to this question?
3
Why is this the correct answer?
The van’t Hoff factor compares the total number of particles present after dissociation with the number of original formula units. One formula unit of AB2 produces one A2+ ion and two B− ions, making three particles in total. Under the stated assumption of complete and ideal dissociation, i = 3. No additional particles or association effects are included in this calculation.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
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