If a gas has very low solubility in a liquid, how will its Henry's law constant generally be?
Answer and explanation
Correct answer: High
Using p = K_H x, at a fixed pressure a gas with low solubility has a small dissolved mole fraction x. To produce the same p with a small x, K_H must be relatively large. Therefore, under this common convention, low solubility corresponds to a high Henry's law constant. The constant is not normally zero or negative for this physical situation.
Frequently asked questions
What is the correct answer to this question?
High
Why is this the correct answer?
Using p = K_H x, at a fixed pressure a gas with low solubility has a small dissolved mole fraction x. To produce the same p with a small x, K_H must be relatively large. Therefore, under this common convention, low solubility corresponds to a high Henry's law constant. The constant is not normally zero or negative for this physical situation.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
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