If 20 mL ethanol and 80 mL water are mixed to form a solution, what volume percentage is assumed?
Answer and explanation
Correct answer: 20 percent
Volume percent is calculated as volume of the specified solute divided by the final solution volume, multiplied by 100. Under the question’s stated assumption that volumes are additive, total volume is 20 + 80 = 100 mL. Ethanol volume percent is therefore (20/100) × 100 = 20%. In real mixtures volume contraction may occur, but no contraction is supplied here.
Frequently asked questions
What is the correct answer to this question?
20 percent
Why is this the correct answer?
Volume percent is calculated as volume of the specified solute divided by the final solution volume, multiplied by 100. Under the question’s stated assumption that volumes are additive, total volume is 20 + 80 = 100 mL. Ethanol volume percent is therefore (20/100) × 100 = 20%. In real mixtures volume contraction may occur, but no contraction is supplied here.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
