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If 1 mol solute is dissolved in 2 kg solvent, what is the molality?

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Answer and explanation

Correct answer: 0.5 m

Molality is the number of moles of solute divided by the mass of solvent in kilograms: m = nsolute/mass of solvent. Substituting the data gives m = 1 mol/2 kg = 0.5 mol kg⁻¹, written as 0.5 m. Hence option A is correct. The denominator is solvent mass, not solution volume or total solution mass.

Related tags

MolalityConcentration MetricsSolutionsBasic CalculationChapter 01: SolutionsChapter 01 SolutionsChemistryClass 11 Mcq

Frequently asked questions

What is the correct answer to this question?

0.5 m

Why is this the correct answer?

Molality is the number of moles of solute divided by the mass of solvent in kilograms: m = nsolute/mass of solvent. Substituting the data gives m = 1 mol/2 kg = 0.5 mol kg⁻¹, written as 0.5 m. Hence option A is correct. The denominator is solvent mass, not solution volume or total solution mass.

Which subject and chapter does this question cover?

This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.

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