How much water should be added to 100 mL of 5 M solution to prepare a 0.5 M solution?
Answer and explanation
Correct answer: 900 mL
During dilution, the amount of solute remains constant, so M1V1 = M2V2. Substitution gives 5 × 100 mL = 0.5 × V2, hence V2 = 1000 mL. This is the final volume of the diluted solution. The initial volume was 100 mL, therefore the volume of water added is 1000 − 100 = 900 mL. Option C is correct; choosing 1000 mL confuses final volume with added water.
Frequently asked questions
What is the correct answer to this question?
900 mL
Why is this the correct answer?
During dilution, the amount of solute remains constant, so M1V1 = M2V2. Substitution gives 5 × 100 mL = 0.5 × V2, hence V2 = 1000 mL. This is the final volume of the diluted solution. The initial volume was 100 mL, therefore the volume of water added is 1000 − 100 = 900 mL. Option C is correct; choosing 1000 mL confuses final volume with added water.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Some Basic Concepts of Chemistry. Topic: Mole concept and molar mass.
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