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Class 11ChemistryChapter 01: SolutionsMediumLevel 6

How much sodium carbonate is needed for 1 L of a 0.1 mol L−1 solution if its molar mass is 106 g mol−1?

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Answer and explanation

Correct answer: 10.6 g

For solution preparation, first find required moles using n = M × V. Here n = 0.1 mol L−1 × 1 L = 0.1 mol. Convert moles to mass using m = n × molar mass = 0.1 × 106 = 10.6 g. Therefore, option B is correct. The value 106 g would represent one mole, giving a 1.0 M solution in one litre.

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solutionsmass preparationmolaritymolar massChemistryClass 11 MCQChapter 01: Solutionschapter 01 solutions

Frequently asked questions

What is the correct answer to this question?

10.6 g

Why is this the correct answer?

For solution preparation, first find required moles using n = M × V. Here n = 0.1 mol L−1 × 1 L = 0.1 mol. Convert moles to mass using m = n × molar mass = 0.1 × 106 = 10.6 g. Therefore, option B is correct. The value 106 g would represent one mole, giving a 1.0 M solution in one litre.

Which subject and chapter does this question cover?

This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.

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