How many moles of solute are present in 250 mL of a 2 M solution?
Answer and explanation
Correct answer: 0.5 mole
The governing relation is M = n/V, so the amount of solute is n = M × V. Volume must be expressed in litres: 250 mL = 0.250 L. Therefore n = 2 mol L⁻¹ × 0.250 L = 0.500 mol. Option A is correct. The value 2 is the molarity, while using 250 without conversion would produce an invalid result because the units would not cancel properly.
Frequently asked questions
What is the correct answer to this question?
0.5 mole
Why is this the correct answer?
The governing relation is M = n/V, so the amount of solute is n = M × V. Volume must be expressed in litres: 250 mL = 0.250 L. Therefore n = 2 mol L⁻¹ × 0.250 L = 0.500 mol. Option A is correct. The value 2 is the molarity, while using 250 without conversion would produce an invalid result because the units would not cancel properly.
Which subject and chapter does this question cover?
This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.
