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An electrolyte X₂Y₃ gives how many ions on complete dissociation, and what is i at 50% dissociation?

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Answer and explanation

Correct answer: Five ions and 3.0

One formula unit of X₂Y₃ produces 2X ions and 3Y ions on complete dissociation, giving n = 5 total ions. For an electrolyte that dissociates into n particles, i = 1 + α(n − 1). With α = 0.50 and n = 5, i = 1 + 0.50(4) = 3.0. The calculation counts every individual ion, not merely the number of different ion types. Therefore, option A is correct.

Tags

electrolyte dissociationvan’t Hoff factormulti-ion electrolytecolligative propertiesChapter 01: Solutionschapter 01 solutionsChemistryClass 11 MCQ

Frequently asked questions

What is the correct answer to this question?

Five ions and 3.0

Why is this the correct answer?

One formula unit of X₂Y₃ produces 2X ions and 3Y ions on complete dissociation, giving n = 5 total ions. For an electrolyte that dissociates into n particles, i = 1 + α(n − 1). With α = 0.50 and n = 5, i = 1 + 0.50(4) = 3.0. The calculation counts every individual ion, not merely the number of different ion types. Therefore, option A is correct.

Which subject and chapter does this question cover?

This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.

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