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A 98 percent by mass sulfuric acid solution has density 1.84 g mL−1. What is its molarity?

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Answer and explanation

Correct answer: 18.4 mol L−1

Choose 1 L of solution. Its mass is 1.84 g mL−1 × 1000 mL = 1840 g. The mass of H2SO4 is 98% of this, or 1803.2 g. Using molar mass 98 g mol−1 gives 1803.2/98 = 18.4 mol. Since these moles are in 1 L, the molarity is 18.4 mol L−1. Density is essential in this conversion.

Tags

solutionsmolarityChapter 01: Solutionschapter 01 solutionsChemistryClass 11 MCQ

Frequently asked questions

What is the correct answer to this question?

18.4 mol L−1

Why is this the correct answer?

Choose 1 L of solution. Its mass is 1.84 g mL−1 × 1000 mL = 1840 g. The mass of H2SO4 is 98% of this, or 1803.2 g. Using molar mass 98 g mol−1 gives 1803.2/98 = 18.4 mol. Since these moles are in 1 L, the molarity is 18.4 mol L−1. Density is essential in this conversion.

Which subject and chapter does this question cover?

This is a Class 11 Chemistry question. Chapter: Chapter 01: Solutions.

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